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Can pls someone help me plsss I need help :(

Can Pls Someone Help Me Plsss I Need Help class=

Sagot :

Answer: [tex]7,5.66,39^{\circ}[/tex]

Step-by-step explanation:

Given

[tex]IJ=9\\\angle I=51^{\circ}[/tex]

from figure, we can write

[tex]\Rightarrow \sin 51^{\circ}=\dfrac{HJ}{9}\\\\\Rightarrow HJ=9\sin 51^{\circ}=6.99\approx 7[/tex]

[tex]\Rightarrow \cos 51^{\circ}=\dfrac{HI}{9}\\\Rightarrow HI=9\cos 51^{\circ}\\\Rightarrow HI=5.66[/tex]

In right angle trianle, the sum of the remaining two angles is [tex]90^{\circ}[/tex]

[tex]\therefore 51^{\circ}+\angle J=90^{\circ}\\\Rightarrow \angle J=90^{\circ}-51^{\circ}\\\Rightarrow \angle J=39^{\circ}[/tex]

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