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Sagot :

Answer:

[tex]y' = (6,4)[/tex]

Step-by-step explanation:

Given

[tex]y = (3,2)[/tex]

[tex]x = (4,0)[/tex]

[tex]z = (2,-2)[/tex]

[tex]D_{(O,2)}[/tex]

Required

The image of y

[tex]D_{(O,2)}[/tex] implies that y is dilated by a scale factor of 2 across the origin.

So, the image of y is:

[tex]y' = 2 * y[/tex]

[tex]y' = 2 * (3,2)[/tex]

[tex]y' = (6,4)[/tex]