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Mr. and Mrs. Doran have a genetic history such that the probability that a child being
born to them with a certain trait is 2/5. If they have seven children, what is the
probability that exactly six of their seven children will have that trait? Round your
answer to the nearest thousandth.


Sagot :

Answer: [tex]0.017[/tex]

Step-by-step explanation:

Given

the Probability that a child will born with a certain trait is [tex]\frac{2}{5}[/tex]

So, the probability that child does not possess that certain trait is [tex]\frac{3}{5}[/tex]

The probability that exactly six of their children has that trait is

[tex]\Rightarrow (\dfrac{2}{5})^6\cdot (\dfrac{3}{5})[/tex]

For 7 children it is

[tex]\Rightarrow 7\times (\dfrac{2}{5})^6\cdot (\dfrac{3}{5})\\\\\Rightarrow 0.017[/tex]

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