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Sagot :
Answer: [tex]0.017[/tex]
Step-by-step explanation:
Given
the Probability that a child will born with a certain trait is [tex]\frac{2}{5}[/tex]
So, the probability that child does not possess that certain trait is [tex]\frac{3}{5}[/tex]
The probability that exactly six of their children has that trait is
[tex]\Rightarrow (\dfrac{2}{5})^6\cdot (\dfrac{3}{5})[/tex]
For 7 children it is
[tex]\Rightarrow 7\times (\dfrac{2}{5})^6\cdot (\dfrac{3}{5})\\\\\Rightarrow 0.017[/tex]
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