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Sagot :
Answer:
4/16
Explanation:
It is given that the alleles of the first locus = A dominant and recessive a
The allele of the second locus = B dominant and the recessive b.
Now if fish with AABB mates with the aabb fishes, then to tell the proportion of the F2 fish which shows either the dominant phenotype at the [tex]$\text{first locus}$[/tex] and also a recessive phenotype at the [tex]$\text{second locus}$[/tex].
So for this, the recessive phenotype at the [tex]$\text{first locus}$[/tex] as well as the recessive phenotype at the [tex]$\text{second locus}$[/tex] is in the ratio of 4/16.
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