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Sagot :
Answer:
the frequency of the fog horn with a higher pitch is 177.07 Hz
Explanation:
Given the data in the question;
time between a minimum and the next maximum in loudness = 0.14 seconds
So,
Time T between the two continuous maximum in loudness will be;
⇒ T = 2 × 0.14 sec
T = 0.28 seconds
Thus, beat frequency [tex]f_b[/tex] will be;
[tex]f_b[/tex] = 1 / T
we substitute in the value of T
[tex]f_b[/tex] = 1 / 0.28
[tex]f_b[/tex] = 3.5714 Hz
Now, we know that; [tex]f_b[/tex] = [tex]f_2[/tex] - [tex]f_1[/tex]
we solve for [tex]f_2[/tex]
[tex]f_2[/tex] = [tex]f_b[/tex] + [tex]f_1[/tex]
given that; the lower pitch has a frequency of 173.5 Hz
we substitute
[tex]f_2[/tex] = 3.5714 Hz + 173.5 Hz
[tex]f_2[/tex] = 177.07 Hz
Therefore, the frequency of the fog horn with a higher pitch is 177.07 Hz
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