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Sagot :
Answer:
Test statistic = - 2.29
Pvalue = 0.0110
Step-by-step explanation:
The hypothesis :
H0 : p = 0.3
H1 : p < 0.3
Test statistic :
z=pˆ−p/√p(1−p)/n
pˆ = 0.2
Z = (0.20 - 0.30) / √(0.30(1 - 0.30) / 110
Z = - 0.1 / √0.0019090
Z = - 0.1 / 0.0436931
Z = - 2.29
Test statistic = -2.29
The Pvalue :
P(Z < -2.29) = 0.0110
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