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What volume of 3.00M NaCl is required for a
reaction that requires 146.3g of NaCl?


Sagot :

Answer: 0.834 L

Explanation:

Volume is the scalar quantity that is the space required by the solution or the substance. The volume required for the 146.3g of 3.00M NaCl is 0.834 L.

What is the relationship between volume and molarity?

Molarity is the concentration of the solution and is given as the ratio of the moles and the volume of the solution. The volume of the solution or the solute is inversely proportional to the molarity of the substance.

Molarity is given as,

[tex]\rm Molarity (M) =\rm \dfrac{ Moles(n) }{\text{Volume in L}}[/tex]

Here,

Molarity of sodium chloride = 3.00M

Mass of sodium chloride = 146.3g

Molar mass of sodium chloride = 58.44 g/mol

Substituting values in the equation:

[tex]\begin{aligned} \rm Molarity &= \rm \dfrac{mass}{Molar \;mass \times Volume}\\\\\rm V &= \dfrac{146.3}{ 58.44 \times 3.00}\\\\&= 0.8344 \;\rm L\end{aligned}[/tex]

Therefore, the volume of the sodium chloride required is 0.834 L

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