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Sagot :

Answer:

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

[tex] \huge\red{ \mid{ \underline{ \overline{ \tt Fe }} \mid}}[/tex]

→ Molar Mas = 55.85 g/mol

[tex] \huge\orange{ \mid{ \underline{ \overline{ \tt NaCl }} \mid}}[/tex]

→ Molar Mass = 58.44 g/mol

[tex] \huge\red{ \mid{ \underline{ \overline{ \tt CH₄ }} \mid}}[/tex]

→ Molar Mass = 16.02 g/mol

[tex] \huge\orange{ \mid{ \underline{ \overline{ \tt Ca(OH)₂ }} \mid}}[/tex]

→ Molar Mass = 74.10 g/mol

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]

Answer:

Fe -> 55.85g/mol

NaCl-> 58.44g/mol

CH₄->16.02g/mol

Ca(OH)₂->74.10g/mol

Explanation:

NaCl = 22.990 + 35.45  = 58.44g/mol

CH₄ = 12.011 + (1.008 × 4) = 16.043 g/mol

Ca(OH)₂ = 40.078  + 2(15.999 + 1.008) = 74.092 g/mol