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The brakes applied to a car
produce an acceleration of 6 m s-²
the opposite direction to the motion. If
the car takes 2 seconds to stop after the
application of brakes, calculate the
distance it travels during this time.​

Sagot :

Explanation:

[tex]from \: newton \: first \: equation \\ V = U + at \\ 0 = U + ( - 6 \times 2) \\ U = 12 \: m {s}^{ - 1} \\ from \: newtons \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {12}^{2} + (2 \times - 12 \times \: S ) \\ 144 = 24S \\S = 6 \: m [/tex]

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