Answered

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1. If you have 200 g of Al2(CO3)3 , how many moles will you have? Show your work.

Sagot :

Answer: There are 0.854 moles of [tex]Al_{2}(CO_{3})_{3}[/tex] present in 200 g of [tex]Al_{2}(CO_{3})_{3}[/tex].

Explanation:

Given: Mass of [tex]Al_{2}(CO_{3})_{3}[/tex] = 200 g

As number of moles is the mass of substance divided by its molar mass.

Molar mass of [tex]Al_{2}(CO_{3})_{3}[/tex] is 233.99 g/mol.

Therefore, moles of [tex]Al_{2}(CO_{3})_{3}[/tex] is calculated as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{200 g}{233.99 g/mol}\\= 0.854 mol[/tex]

Thus, we can conclude that there are 0.854 moles of [tex]Al_{2}(CO_{3})_{3}[/tex] present in 200 g of [tex]Al_{2}(CO_{3})_{3}[/tex].

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