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Sagot :
The ratio of the speed of this ray in diamond to its speed in zircon will be 31:39. The refractive index formula is used in this problem.
What is the frequency of light rays?
The speed during which light rays travel through various materials is referred to as the speed of light.
In particular, the speed of light in a vacuum has now been determined to be 3 ×10⁸ meters per second.
The refractive index of the diamond is found as;
[tex]\rm n = \frac{c}{v} \\\\ \rm 2.42 = \frac{3 \times 10^8}{v} \\\\ v_{diamond}= 1.24 \times 10^8 \ m/sec[/tex]
The refractive index of the zircon is found as;
[tex]\rm n= \frac{c}{v} \\\\\ 1.93 = \frac{36 \times 10^8}{v_{zircon}} \\\\ v_{zircon}= 1.56 \times 10^8 \ m/sec[/tex]
The ratio of the speed of this ray in diamond to its speed in zircon will be;
[tex]\rm \frac{v_{diamond}}{v{zircon}} = \frac{1.24 \times 10^8 }{1.56 \times 10^8} \\\\ \rm \frac{v_{diamond}}{v{zircon}} = \frac{1.24}{1.56} \\\\ \frac{v_{diamond}}{v{zircon}} = \frac{31}{39}[/tex]
Hence the ratio of the speed of this ray in diamond to its speed in zircon will be 31:39.
To learn more about the frequency of light rays refer to the link;
https://brainly.com/question/23281551
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