wolfboy0829
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Solve each system by substitution. Show your work.

1) y = -3x - 1

y = 3x - 7


2) y = 7x + 16

y = 4x + 10


3) y = -3x - 5

y = 8x + 17


4) y = -2x + 4

y = x + 1






5) y = 6x + 8

y = 2x + 4


6) y = 7x + 7

2x - 4y = -2


7) -5x - 6y = -22

y = -7x + 16


8) -5x - y = 17

y = -6x - 22


9) y = 7x - 5 -8x + 3y = -2


10) y = 8x - 7 -7x - 7y = -14


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-3-


11) 4x - 3y = 19 -3x + y = -18


12) 7x + y = 0

7x - 7y = 0


13) x - y = 4

7x + 3y = -12


14) 5x + 7y = 7

x + 5y = 5


15) -6x - 6y = 0

5x + y = 8


16) -2x - 2y = 12 -7x + 7y = 0


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-4-


17) 6x - 3y = 6

8x - 5y = 8


18) -4x - 7y = -16

6x - y = -22


19) -4x - 5y = 16

5x + 7y = -23


20) -4x - 4y = -20

4x + 3y = 19

Sagot :

1) y = -3x - 1
Y= 3x - 7

- 3x -1= 3x -7
Like terms
-3x -3x = -7 + 4
A negative and a negative is a positive
-3x + - 3x = -6x because a positive and a negative is a negative
-7 + 1 = - 6
Hence
- 6 x = -6
Divide both sides by -6
Which gives u
X = 1
Now substitute x = 1 into one of the original equations
Y = 3x - 7
Y = 3*1 - 7
Y = 3 - 7
Look at the bigger number sign
Therefore
Y = - 4
So when x = 1, y = -4
It’s really the same for the rest of the questions to be honest


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