Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The vertex of the parabola f(x) = 2x^2 - 4x + 6 is (1, 4)
How to graph the parabola?
The function is given as:
f(x) = 2x^2 - 4x + 6
Differentiate the function
f'(x) = 4x - 4
Set to 0
4x -4 =0
So, we have:
4x = 4
Divide by 4
x = 1
Substitute x = 1 in f(x) = 2x^2 - 4x + 6
f(1) = 2(1)^2 - 4(1) + 6
This gives
f(1) = 4
This means that the vertex is (1, 4)
Next, we set x = 0.
So, we have:
f(0) = 2(0)^2 - 4(0) + 6
This gives
f(0) = 6
This means that the parabola passes through the point (0, 6)
See attachment for the parabola
Read more about parabola at:
https://brainly.com/question/21685473
#SPJ1
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.