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Use the parabola tool to graph the quadratic function f (x) = 2x2 - 4x + 6.
Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.


Sagot :

The vertex of the parabola f(x) = 2x^2 - 4x + 6 is (1, 4)

How to graph the parabola?

The function is given as:

f(x) = 2x^2 - 4x + 6

Differentiate the function

f'(x) = 4x - 4

Set to 0

4x -4 =0

So, we have:

4x = 4

Divide by 4

x = 1

Substitute x = 1 in f(x) = 2x^2 - 4x + 6

f(1) = 2(1)^2 - 4(1) + 6

This gives

f(1) = 4

This means that the vertex is (1, 4)

Next, we set x = 0.

So, we have:

f(0) = 2(0)^2 - 4(0) + 6

This gives

f(0) = 6

This means that the parabola passes through the point (0, 6)

See attachment for the parabola

Read more about parabola at:

https://brainly.com/question/21685473

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