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What is the total number of moles of ions produced by dissolving 0.5 mole of aluminum sulfate, Al2(So4)3 in water?

Sagot :

maacastrobr

Answer:

2.5 moles of ions

Explanation:

In order to solve this problem, first we need to determine how many moles of ions are there in one mol of aluminum sulfate:

  • 1 Al₂(SO₄)₃ mol contains 2 Al⁺³ moles and 3 SO₄⁻³ moles, meaning that in total it contains 5 moles of ions.

With the above information in mind we can proceed to calculate how many moles of ions would there be in 0.5 moles of Al₂(SO₄)₃:

  • 0.5 mol Al₂(SO₄)₃ * [tex]\frac{5molesOfIons}{1molAl_2(SO_4)_3}[/tex] = 2.5 moles of ions
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