Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Temporary Help Answer
The answer is limited due to the lack of questions, so I'll give you some answers related.
State appropriate Hypothesis for performing a significance test. Be sure to define the parameter of interest. (u = mu)
[tex]H_{null}:u=17 \\H_{a}:u<17[/tex] Where mu = the true mean of almonds in each bar of candy.
Calculate the test statistic and the P-Value.
mu = 17
x-bar = 14
[tex]S_{x} = 8[/tex]
[tex]n = 30[/tex]
Use the T-Test (STAT) if you have a Graphing Calculator.
Interpret the P-Value in context.
Assuming the mean number of almonds in each candy bar is 17, there is a [P-Value] probability of getting a sample mean of 14 by chance alone.
What is the decision at the given significance level?
P-val of [P-Value] is (> or <?) to the alpha level [[tex]a[/tex]], so you must (fail to reject or reject?) the Null Hypothesis.
What do you conclude? (If P-val is smaller than the alpha level, reject the null hypothesis, meaning there is significant evidence.)
Because the P-Value of [P-Value] is (less/greater) than [tex]a = (?)[/tex], the observed result (is or is not?) statistically significant. There (is or is not?) significant evidence to conclude that the chocolate almond bars contain fewer almonds than they've previously contained.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.