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If 5.00 g of Gas A and 5.00 g of Gas B are mixed in the same container, and the partial pressure of Gas B is determined to be twice that of Gas A, what do we know about the gases? A) Gas A has half the molar mass of Gas B. B) Gas A has twice the molar mass of Gas B. C) Gas A has a higher temperature than Gas B. D) Gas A takes up twice the volume in the vessel than Gas B.

Sagot :

jufsanabriasa

Answer:

B) Gas A has twice the molar mass of Gas B.

Explanation:

Partial pressure of a gas is defined as the moles of the gas/ Total moles of the mixture times total pressure. The equation is:

Partial pressure A = Moles A / total moles * Total pressure

From the definition, we can say that the moles of the gas A are twice the moles of B:

2 Moles A = Moles B

As the mass of both gases is the same but the moles of B are twice the moles of A:

The molar mass of A is twice the molar mass of B

Right answer is:

B) Gas A has twice the molar mass of Gas B.

okpalawalter8

We have that for the Question " what do we know about the gases?"

It can be said that

  • B) Gas A has twice the molar mass of Gas B [tex]M_A=2M_B[/tex]

From the question we are told

5.00 g of Gas A and 5.00 g of Gas B are mixed in the same container, and the partial pressure of Gas B is determined to be twice that of Gas A

The equation for partial pressure gasA and gasB is given as

[tex]Partial Pressure = \frac{number of moles of }{Total no of moles of gas}[/tex]

That results to,

[tex]\frac{Partial pressure of A}{Partial pressure of B} = \frac{no of moles of A}{no of moles of B}[/tex]

[tex]= \frac{Given mass A}{Molar mass A} * \frac{Molar mass B}{Given mass B}\\\\= \frac{1}{2} = \frac{5*M_B}{M_A*5}\\\\= \frac{1}{2} = \frac{M_B}{M_A}\\\\= M_A = 2M_B[/tex]

For more information on this visit

https://brainly.com/question/17756498

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