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help please, it’s on my physics paper!

Help Please Its On My Physics Paper class=

Sagot :

talhabhuta1

Answer:

15.4

Explanation:

770x14% = 107.8

rearrange f =kx to get k (constant)

k = f/x

x is the distance stretched , so 42 - 35 =7

so 107.8/7 =15.4

can someone double check

samuelpoly011

Answer:

k = 44000 N/m is the answer.

Explanation:

Gravitational Potential Energy = 770J

Elastic Potential Energy = 14% of 770J

= 14/100 × 770

= 107.8J

Extension (x) = 42 - 35 = 7cm = 7 × 10⁻²m

To find the spring constant (k)

Elastic Potential Energy Formula:

[tex]U = \frac{1}{2}kx^2[/tex]

107.8 = 1/2 × k × (7 × 10⁻²)²

215.6 = 0.0049 × k

k = 215.6/0.0049

k = 44000 N/m

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