Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
[tex]M_{C_5H_5N}\times V_{C_5H_5N}= M_{HNO_3}\times V_{HNO_3}[/tex]
[tex]0.0750 M \times 2.65 L = 0.407 M \times V_{HNO_3}[/tex]
[tex]V_{HNO_3}= \dfrac{0.0750 M \times 2.65 L}{0.407 M}[/tex]
[tex]V_{HNO_3}=488.33 \ mL[/tex]
The reaction between C5H5NH and H2O is as follows:
[tex]C_5H_5N^+H + H_2O[/tex] ⇄ [tex]C_5H_5N + H_3O^+[/tex]
[tex]Molarity \ of \ C_5H_5N^+H = \dfrac{moles}{addition \ of\ the\ total\ volume}[/tex]
[tex]Molarity \ of \ C_5H_5N^+H = \dfrac{0.0750 \ M \times 2.65 \ L}{2.65 \ L + 0.48833 \ L}[/tex]
[tex]Molarity \ of \ C_5H_5N^+H = \dfrac{0.19875 \ ML}{3.13833 L }[/tex]
[tex]= \ 0.06333\ M[/tex]
Now, the next step is to draw out the I.C.E table.
[tex]C_5H_5N^+H + H_2O[/tex] ⇄ [tex]C_5H_5N + H_3O^+[/tex]
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
[tex]K_a = \dfrac{10^{-14}}{1.7 \times 10^{-19}} \\ \\ K_a = 5.8824 \times 10^{-6}[/tex]
[tex]K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}[/tex]
Assuming x < 0.06333
[tex]x^2 = 5.8824 \times 10^{-6} \times 0.06333[/tex]
Then
[tex]x^2 = 3.72532392 \times 10^{-7} \\ \\ x= \sqrt{3.72532392 \times 10^{-7}} \\ \\ x = 6.1035 \times 10^{-4} \ M[/tex]
[tex][H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}[/tex]
The pH for HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5H5N, Kb = 1.7 × 10−9) is
HNO3 + C5H5N→CSH5NH + + NO3
Moles of C5H5N = volume x concentration
=2.65 x 0.0750
=0.1987 mol
Moles of HNO3 needed = moles of C5H5N = 0.19875 mol Volume of HNO3 eeded = moles / con
=0.19875/0.54
=0.363L
=363 mL
At the equivalence point, most effective C5H5NH + a NO3-are Moles of C5H5NH+ = moles of C5H5N = 0.19875 mol
Total extent of answer n = 2.65 + 0.363 =3.013 L
Initial concentration [ C5H5NH + ] o = moles/ volume =0.19875/3.013 =0.06596 M
Kb of C5H5N = 1.7 x 10 ^ 9
By fixing the equation,
H + = 6.199 * 10 ^ 4 M
pH=-log[H+]
=3.207
=3.21 pH
What is pH ?
The pH is the degree of ways acidic or simple a substance is. In humans, pH stability performs a position in preserving the frame functioning optimally. The best pH of the frame is barely alkaline, which helps sure biochemical reactions like oxygenating the blood.
Thus it is clear above.
To learn more aboyt the titration refer to link :
https://brainly.com/question/186765
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
