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A swimmer in the ocean observes one day that the ocean surface waves are periodic and resemble a sine wave. The swimmer estimates that the vertical distance between the crest and the trough of each wave is approximately 0.520 m, and the distance between each crest is approximately 2.10 m. The swimmer counts that 22.0 waves pass every minute. Determine the speed of these waves.

Sagot :

Answer:

Explanation:

wave length is distance between each crest so if wavelength be λ

λ = 2.10 m

frequency is no of waves passing a particular point per second .

If frequency be represented by n

n = 22 / 60 per second .

velocity of wave v = n x λ

= (22 / 60 ) x 2.1 m /s

= .77 m /s

= 77 cm /s .

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