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A board of length 16 ¾ inches is cut into 4 equal pieces. If 7/8 of an inch is then removed from one of these pieces, what is the length of that piece?

Sagot :

Answer: [tex]\dfrac{53}{16}\ \text{or}\ 3\dfrac{5}{16}[/tex]

Step-by-step explanation:

Given

Length of board is [tex]16\ \frac{3}{4}[/tex]

It is divided into 4 equal pieces i.e. length of each piece is

[tex]\Rightarrow \dfrac{\frac{64+3}{4}}{4}=\dfrac{67}{16}\ \text{in.}[/tex]

If  [tex]\frac{7}{8}[/tex] of an inch is removed from one of the pieces then,

[tex]\Rightarrow \dfrac{67}{16}-\dfrac{7}{8}\\\\\Rightarrow \dfrac{67}{16}-\dfrac{14}{16}=\dfrac{53}{16}\ \text{inch}[/tex]