At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let n be the unknown number. We can write it as
n = 10a + b
with a and b integers between 1 and 9 (either with positive or negative sign).
Reversing the digits gives another number
m = 10b + a
The first number is increased by 54 when the digits are reversed, which means
m = n + 54 → 10b + a = 10a + b + 54 → 9b - 9a = 54 → b - a = 6
The digit in the tens place of n is 3 times the digit in the ones place, so
a = 3b
Substitute this into the previous equation and solve for b :
b - a = b - 3b = -2b = 6 → b = -3
Solve for a :
a = 3b = 3(-3) = -9
Then the original number is n = 10a + b = 10(-9) + (-3) = -93
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.