Answer:
(a)
[tex]Area= 27ft^2[/tex] --- the catboat
[tex]Area = 25ft[/tex] --- the sloop
(b)
[tex]Cost = \$40.5[/tex] -- the catboat
[tex]Cost = \$37.5[/tex] --- the sloop
Step-by-step explanation:
Incomplete question (See attachment)
For the catboat, we have:
[tex]Base = 9ft\\Height = 6ft[/tex]
For the Sloop, we have:
[tex]Base = 7 + 3 = 10ft[/tex]
[tex]Height = 5ft[/tex]
Solving (a): The area of both sailboats.
Since both are triangular, we use:
[tex]Area= 0.5 * Base * Height[/tex]
For the catboat
[tex]Area= 0.5 * 9ft*6ft[/tex]
[tex]Area= 27ft^2[/tex]
For the sloop
[tex]Area = 0.5 * 10ft * 5ft[/tex]
[tex]Area = 25ft[/tex]
The catboat has the greater sail area because 27 > 25
Solving (b): Cost of sail for each.
We have the unit price to be:
[tex]Unit = \$1.50/ft^2[/tex]
So, the cost is calculated by multiplying the unit price by the total area.
So, we have:
For the catboat;
[tex]Cost = 27ft^2 * \$1.50/ft^2[/tex]
[tex]Cost = \$40.5[/tex]
For the sloop
[tex]Cost = 25ft^2 * \$1.50/ft^2[/tex]
[tex]Cost = \$37.5[/tex]
