Correct question:
Imagine that a 1200 kg vehicle speeds up from rest to 20.0 m/s in 80 s.
How much work was done on the car? (Answer in 3 sig figs)
Answer:
the work done on the vehicle is 2.40 x 10⁵ J
Explanation:
Given;
mass of the vehicle, m = 1200 kg
initial velocity of the vehicle, u = 0
final velocity of the vehicle, v = 20 m/s
time of motion of the vehicle, t = 80 s
The distance moved by the vehicle is calculated as;
[tex]s = (\frac{v + u}{2} )t\\\\s = (\frac{20+ 0}{2} )(80)\\\\s = 800 \ m[/tex]
The force applied to the vehicle is calculated as;
[tex]F = ma = \frac{m v}{t} = \frac{1200 \times 20}{80} = 300 \ N\\\\[/tex]
The work done on the vehicle is calculated as;
W = F x d
W = 300 x 800
W = 2.4 x 10⁵ J.
Therefore, the work done on the vehicle is 2.40 x 10⁵ J
