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Sagot :
Answer:
LCL = 4.72
UCL = 18.08
Step-by-step explanation:
Sample size, n = 20
Sample _ tread wear, x __ Range
1 ______ 33.67 ___ 14
2______ 26.33 ___ 17
3 _____ 29.67 ____ 9
4 ______ 21 ______ 8
5 ______ 34 ______ 9
6 ______ 39.67 ___ 6
7 ______ 22.33 ___ 12
8 ______ 28.67 ___ 6
9 ______ 36 ______8
10 _____ 25.33 ___ 13
11 _____ 32.33 ____14
12 _____ 22.33 ___ 6
13 _____ 24.33 ___ 15
14 _____ 31.67 ___ 26
15 _____ 24 _____ 11
16 ____ 34.33 ____ 12
17 ____ 32 _______ 8
18 ____ 33.33 ____ 11
19 ____ 25 _______11
20 ___ 27.33 _____12
Sample mean, xbar = Σx / n = 29.167
Rbar = ΣR/ n = 11.4
The R chart control limit is given by :
Rbar(1 - 3(d3/d2))
From the R chart :
d3 = 0.729 ; d2 = 3.735
Hence,
LCL = 11.4(1 - 3(0.729/3.735))
LCL = 11.4(0.4144578) =
LCL = 4.72481892 = 4.72
UCL = 11.4(1 - 3(0.729/3.735))
UCL = 11.4(1.5855421)
UCL = 18.075180 = 18.08
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