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A quadratic equation has an acis of symetry x=-1. If one point ia located at 6,2 what is the other point on the quadratic equation

Sagot :

facundo3141592

Answer:

The other point is (-8, 2)

Step-by-step explanation:

A general quadratic equation is something like:

f(x) = a*x^2 + b*x + c

Where a, b, and c are real numbers.

If the function has an axis of symmetry at x₀, this means that:

f(x₀ + x) = f(x₀ - x)

for all values of x.

In this case we have:

x₀ = -1

Then:

f(-1 + x) = f(-1 - x)

Now we know that the point (6, 2) is a solution of the quadratic equation

This means that f(6) = 2

If we write 6 = -1 + x

We can solve this for x to get:

6 = -1 + x

6 + 1 = x = 7

Then we will have:

2 = f(6) = f(-1 + 7) = f(-1 - 7) = f(-8)

Then:

f(-8) = 2

sThis means that the other point on the quadratic eqation is (-8, 2)

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