At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

In horses, the allele for a bay coat (brown with black mane, tail, and legs) and the allele for a cream coat can combine to make a
buckskin coat. The allele c is used for bay: CC is used for cream. Buckskin horses have one bay and one cream allele. The
genotype cc makes a buckskin coat, as neither allele is dominant. Cross a bay stallion (father) with a buckskin mare (mother).
How many offspring will have the same phenotypes as the mother.
Please help me


In Horses The Allele For A Bay Coat Brown With Black Mane Tail And Legs And The Allele For A Cream Coat Can Combine To Make A Buckskin Coat The Allele C Is Used class=

Sagot :

Answer:

100%

Explanation:

By crossing a bay stallion with a buckskin mare, 100% of offspring will have the same phenotypes as the mother (i.e., buckskin mare).

  • An allele is a gene variant, diploid organisms (like horses) inherit two alleles for a given gene locus, one allele from the mother and another from the father.

  • In complete dominance, the dominant allele completely masks the expression of the recessive allele in heterozygous individuals.

  • In codominance, both alleles are expressed in order to produce a given phenotype.

In conclusion, by crossing a bay stallion with a buckskin mare, 100% of offspring will have the same phenotypes as the mother (i.e., buckskin mare).

Learn more in:

https://brainly.com/question/3578928