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A 2.50 L balloon is filled with water at 2.27 atm. If the balloon is squeezed into a 0.80 L beaker and does NOT burst, what is the pressure of water in the balloon?

Sagot :

sebassandin

Answer:

[tex]P_2=7.09atm[/tex]

Explanation:

Hello!

In this case, given the change in volume and pressure of the gas, it is possible for us to recall the Boyle's law as way to understand the inversely proportional relationship between pressure and volume:

[tex]P_1V_1=P_2V_2[/tex]

Thus, when solving for the final pressure, P2, given the initial pressure and volume and the final volume, we obtain:

[tex]P_2=\frac{P_1V_1}{V_2}\\\\P_2=\frac{2.27atm*2.50L}{0.80L}\\\\P_2=7.09atm[/tex]

Best regards!

Answer:

7.1 atm

Using Boyle’s law, P1 V1=P2 V2.

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