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How big of an electric field exists when an electric force of 2 Newtons is exerted on a charge of 1.602 x 10^-19 Coulombs? *

Sagot :

onyebuchinnaji

Answer:

The electric field experienced by the charge is 1.248 x 10¹⁹ N/C

Step-by-step explanation:

Given;

the magnitude of the force, F = 2 N

the magnitude of the charge, q = 1.602 x 10⁻¹⁹ C

The electric field experienced by the charge is calculated as follows;

[tex]E = \frac{F}{q} \\\\E = \frac{2}{1.602 \times 10^{-19} \ } \\\\E = 1.248 \times 10^{19} \ N/C[/tex]

Therefore, the electric field experienced by the charge is 1.248 x 10¹⁹ N/C.

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