roserosemusic21
Answered

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Please help me please I reallly need help

Please Help Me Please I Reallly Need Help class=

Sagot :

Answer:

we have:

[tex]v = \frac{1}{3} \pi \: r {}^{2}h \\ \\ = > 60\pi = \frac{1}{3} \pi \: r {}^{2} h \\ \\ < = > 180 = r {}^{2} h[/tex]

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12

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