roserosemusic21
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Please help me please I reallly need help

Please Help Me Please I Reallly Need Help class=

Sagot :

Answer:

we have:

[tex]v = \frac{1}{3} \pi \: r {}^{2}h \\ \\ = > 60\pi = \frac{1}{3} \pi \: r {}^{2} h \\ \\ < = > 180 = r {}^{2} h[/tex]

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.