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Particles q1 = +8.0 °C, 92 = +3.5 uc, and

q3 = -2.5 uC are in a line. Particles qi and q2 are

separated by 0.10 m and particles q2 and q3 are

separated by 0.15 m. What is the net force on

particle qı?

Remember: Negative forces (-F) will point Left

Positive forces (+F) will point Right

-2.5 με

+8.0 μC

+91

+3.5 με

+92

93

K 0.10 m

+

0.15 m

Sagot :

Answer:

Explanation:

q₁ = 8 x 10⁻⁶ C , q₂ = 3.5 x 10⁻⁶ C , q₃ = -2.5  x 10⁻⁶ C

Force between charge = 9 x 10⁹ x q₁ q₂ / d²

Force on q₁ due to q₂

= 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶  /( .10 )²

= 25.2 N . This force will be negative as it will point towards left ( q₂ will repel q₁ )

Force on q₁ due to q₃

= 9 x 10⁹ x 8 x 10⁻⁶ x 2.5 x 10⁻⁶  /( .15 )²

= 8 N . This force will be negative as it will point towards left ( q₃ will attract  q₁ )

Net force = 25.2 N - 8 N

= 17.2 N .