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Sagot :
Answer:
The answer is "Option A (2 days)".
Explanation:
Using formula:
The daily cost for storing the product = [tex]\frac{(\text{Annual Holding cost} \times \text{Product value})}{365}[/tex]
[tex]= \frac{(0.31 \times 152)}{365} \\\\= \frac{(47.12)}{365} \\\\= 0.129[/tex]
The daily cost of storing [tex]330 \ boxes = 330\times 0.129 = \$ 42.601[/tex]
For point A:
For (2 days):
[tex]= 508 + (2\times 42.6) = 593.203[/tex]
For (3 days):
[tex]= 474 + (3\times 42.6) =601.805[/tex]
For (9 days):
[tex]= 410 + (9\times 42.6)= 793.415[/tex]
For point B:
For (2 days):
[tex]= 533 +(2\times 42.6) = 618.203[/tex]
For (4 days):
[tex]= 451 +(4\times 42.6) = 621.407[/tex]
For (7 days):
[tex]= 430 +(7\times 42.6) = 728.212[/tex]
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