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Sagot :
Answer:
The solution is given below
Explanation:
The computation is shown below:
Given that
Mass of plane, m is 631 g = 0.631 Kg
The Time period for one circle is 2.15 s
The Radius of circle = 0.95 m
Now the velocity of the plane, v = rω
where,
angular velocity, ω = (θ ÷ t)
For one complete circle, θ = 2π
and Time period T is provided = 2.15 s
Thus, ω = 2π ÷ T = 2π ÷ 2.15
So, velocity, v = rω
= r × ( 2π ÷ 2.15 )
= 0.95 × (2π ÷2.15)
= 2.776 m/s
The Acceleration of the plane, a = rω^2
= 0.95 × (2π ÷ 2.15)^2
= 8.114 m/s^2
The Net force acting upon the plane, F = Centripetal force i.e.
= mv2 ÷ r
F = mv2 / r
= (0.631 × 2.7762) ÷ 0.95
= 5.118 N
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