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Question for JAFAR2007

Question For JAFAR2007 class=

Sagot :

msm555

Answer:

Solution given:

x²+x-20=0

x²+5x-4x-20=0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

either.

x=-5

or

x=4

Step-by-step explanation:

+ x -20 =0

or, +(5-4)x -20

or,x ²+5x -4x -20=0

or,x(x +5)-4(x+5)=0

or,(x+5)(x-4)=o

either,

x+5=0. x-4=0

or,x=0-5. or,x= 0+4

or,x=-5. or, x=4

hope it is helpful to you ☺️

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