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A truck with a mass of 1520 kg and moving with a speed of 16.0 m/s rear-ends a 663 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. vcar

Sagot :

Manetho

Answer:

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

Explanation:

By law of conservation of momentum  

momentum before collision = momentum after collision

[tex]m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2[/tex]

Since, collision is elastic

[tex]16 = v_2-v_1///v_2 = v_1+16 ....(b)[/tex]

solving the above two equations we get

v_1 = 6.28 m/s and v_2 = 22.28 m/s

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

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