Answered

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What will the following code display? int numbers[4] = { 99, 87 }; cout << numbers[3] << endl; a. 87 b.0 d. 34. What will the following code do? const int SIZE = 5; double x[SIZE]; for(int i = 2; i <= SIZE; i++) { x[i] = 0.0; } garbage This code will not compile a. Each element in the array is initialized to 0.0 b. Each element in the array, except the first, is initialized to 0.0 c. Each element in the array, except the first and the last, is initialized to 0.0 d. An error will occur when the code runs

Sagot :

MrRoyal

Answer:

1. The output is 0

2. Each element in the array is initialized to 0.0

Explanation:

Solving (a): The output of the code

We have:

int numbers[4] = { 99, 87 };

cout << numbers[3] << endl;

The first line initializes the 0 and 1 index of the array to 99 and 87, respectively.

Other elements will be 0, by default.

So, the following code segment will output 0

cout << numbers[3] << endl;

Solving (b): What the given code will do?

The first and second line declares an array of 5 elements

However, the following iteration will only initialize the array with 0.0 starting from the second

for(int i = 2; i <= SIZE; i++) { x[i] = 0.0; }

Because, the counter is initialized to start from the second index.

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