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A sample of radon gas has a volume of 0.650 L at a temperature of -55.0 C. What volume will the gas occupy at 40.0 C, assuming constant pressure?

Sagot :

amyfallout2

Answer:

0.933 L

Explanation:

Since the pressure is the same, we use the equation  [tex]\frac{V_{1}}{T_{1} } = \frac{V_{2} }{T_{2} }[/tex]

V = Volume

T = Temperature

Since we are given the temperature in Celsius, we need to convert it to Kelvin by adding 273:

-55.0 + 273 = 218

40.0 + 273 = 313

[tex]\frac{0.650}{218} = \frac{x}{313}[/tex]

[tex]0.933 = x[/tex]

The gas will occupy a volume of 0.933 L.

(Side note - If the temperature increases, the gas will want to expand, leading to a higher volume.)

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