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Sagot :
Answer:
Solution given;
centre of circle =(6,5)
radius (r)=4units
slope of BC(m1)=[tex] \frac{y2-y1}{x2-x1} [/tex]=[tex] \frac{8-5}{2-6} [/tex]=-¾
since it is perpendicular to tangent
slope of tangant[m2]=?
we have
m1m2=-1
m2=⁴/3
since it passes through (2,8)
we have equation of line
is
(y-y1)=m2(x-x1)
y-8=4/3×(x-2)
3y-24=4x-8
4x-3y-8+24=0
4x-3y+16=0 is a required equation
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