Answered

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PLEASE HELP ASAP!! GIVING AWAY BRAINLY if correct AND PLUS 50 pts

Circle A is located at (6, 5) and has a radius of 4 units. What is the equation of a line that is tangent to circle A from point C (2, 8)?

x = 2
y = −0.75x + 9.5
y = 1.33x + 1.66
x = 8


Please don't waste my points, and please leave an explanation.

Sagot :

msm555

Answer:

Solution given;

centre of circle =(6,5)

radius (r)=4units

slope of BC(m1)=[tex] \frac{y2-y1}{x2-x1} [/tex]=[tex] \frac{8-5}{2-6} [/tex]=-¾

since it is perpendicular to tangent

slope of tangant[m2]=?

we have

m1m2=-1

m2=⁴/3

since it passes through (2,8)

we have equation of line

is

(y-y1)=m2(x-x1)

y-8=4/3×(x-2)

3y-24=4x-8

4x-3y-8+24=0

4x-3y+16=0 is a required equation

View image msm555
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