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Calculate the mass in grams of Potassium Nitrate (KNO3) to make 300.0 mL of a 0.020 M solution?

Sagot :

Answer:

0.606 g of KNO₃.

Explanation:

We'll begin by converting 300 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

300 mL = 300 mL × 1 L / 1000 mL

300 mL = 0.3 L

Next, we shall determine the number of mole of KNO₃ in the solution. This can be obtained as follow:

Volume = 0.3 L

Molarity of KNO₃ = 0.020 M

Mole of KNO₃ =?

Mole = Molarity x Volume

Mole of KNO₃ = 0.020 × 0.3

Mole of KNO₃ = 0.006 mole.

Finally, we shall determine the mass of 0.006 mole of KNO₃. This can be obtained as follow:

Mole of KNO₃ = 0.006 mole.

Molar mass of KNO₃ = 39 + 14 + (16×3)

= 39 + 14 + 48

= 101 g/mol

Mass of KNO₃ =?

Mass = mole × molar mass

Mass of KNO₃ = 0.006 × 101

Mass of KNO₃ = 0.606 g

Thus, 0.606 g of KNO₃ is needed to prepare the solution.