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Sagot :
Answer:
New volume = 18.33 L
Explanation:
Given that,
Initial temperature, [tex]T_1=0^{\circ} C=273.15\ K[/tex]
Initial volume, [tex]V_1=20\ L[/tex]
Final temperature, [tex]T_2=-22.8^{\circ}C=250.35\ K[/tex]
We need to find the final volume when pressure is held constant. The relation between volume and temperature is given by :
[tex]V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{20\times 250.35}{273.15}\\\\V_2=18.33\ L[/tex]
So, the new volume is equal to [tex]18.33\ L[/tex].
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