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A weather balloon calibrated at 0.00 degrees Celsius to have a volume of 20.0 L has what volume in L at -22.8 degrees Celsius pressure is held constant?

Sagot :

Answer:

New volume = 18.33 L

Explanation:

Given that,

Initial temperature, [tex]T_1=0^{\circ} C=273.15\ K[/tex]

Initial volume, [tex]V_1=20\ L[/tex]

Final temperature, [tex]T_2=-22.8^{\circ}C=250.35\ K[/tex]

We need to find the final volume when pressure is held constant. The relation between volume and temperature is given by :

[tex]V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{20\times 250.35}{273.15}\\\\V_2=18.33\ L[/tex]

So, the new volume is equal to [tex]18.33\ L[/tex].