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PLEASE HELPP!!!


given sin 0 = 1/2 and 0 < 0 < pi/2, find 0


PLEASE HELPP Given Sin 0 12 And 0 Lt 0 Lt Pi2 Find 0 class=

Sagot :

Answer:

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Answer:

[tex] \theta = \frac{\pi}{6} [/tex]

Step-by-step explanation:

[tex] \sin \theta = \frac{1}{2} \\ \\ \sin \theta = \sin \: 30 \degree \\ ( \because \: \sin \: 30 \degree = \frac{1}{2}) \\ \\ \implies \: \theta = 30 \degree ( \because \: 0 < \theta < \frac{\pi}{2} ) \\ \\ or \: \: \theta = \frac{\pi}{6} [/tex]

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