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Calculate the specific heat of a substance given that 512 joules of heat is required to raise the temperature of 255.0 g of the substance by 15.0 ºC.

Sagot :

Answer:

[tex]c=0.133\ J/g^{\circ}C[/tex]

Explanation:

Given that,

Heat required, Q = 512 J

Mass of the substance, m = 255 g

The change in temperature, [tex]\Delta T=15^{\circ} C[/tex]

Let c be the specific heat of the substance. We know that the heat required to raise the temperature is given by :

[tex]Q=mc\Delta T[/tex]

Where

c is the specific heat of a substance

So,

[tex]c=\dfrac{Q}{m\Delta T}\\\\=\dfrac{512}{255\times 15}\\\\c=0.133\ J/g^{\circ}C[/tex]

So, the specific heat of the substance is equal to [tex]0.133\ J/g^{\circ}C[/tex].

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