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Calculate the final temperature after 15 joules of heat energy is added to 7.3 g of water at 3.2ºC.

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dsdrajlin

Answer:

3.7 °C

Explanation:

Step 1: Given and required data

  • Added heat (Q): 15 J
  • Mass of water (m): 7.3 g
  • Initial temperature (T₁): 3.2 °C
  • Specific heat capacity of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature (T₂) of the water

We will use the following expression.

Q = c ×m ×(T₂ - T₁)

T₂ = Q / c × m + T₁

T₂ = 15 J / (4.184 J/g.°C) × 7.3 g + 3.2 °C = 3.7 °C

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