VictoriaMia2108
Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Chemistry help!




Zoom in to see better!! ​

Chemistry HelpZoom In To See Better class=

Sagot :

Eduard22sly

Answer:

2.5 moles of Al

Explanation:

We'll begin by calculating the number of mole in 127 g of Al₂O₃. This can be obtained as follow:

Mass of Al₂O₃ = 127 g

Molar mass of Al₂O₃ = 101.961 g/mol

Mole of Al₂O₃ =?

Mole = mass / molar mass

Mole of Al₂O₃ = 127 / 101.961

Mole of Al₂O₃ = 1.25 mole

Finally, we shall determine the number of mole of Al that reacted. This can be obtained as follow:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted to produce 2 moles of Al₂O₃.

Therefore, Xmol of Al will react to produce 1.25 moles of Al₂O₃ i.e

Xmol of Al = (1.25 × 4)/2

Xmol of Al = 2.5 moles.

Thus, 2.5 moles of Al is needed for the reaction.

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.