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Eduard22sly

Answer:

2.5 moles of Al

Explanation:

We'll begin by calculating the number of mole in 127 g of Al₂O₃. This can be obtained as follow:

Mass of Al₂O₃ = 127 g

Molar mass of Al₂O₃ = 101.961 g/mol

Mole of Al₂O₃ =?

Mole = mass / molar mass

Mole of Al₂O₃ = 127 / 101.961

Mole of Al₂O₃ = 1.25 mole

Finally, we shall determine the number of mole of Al that reacted. This can be obtained as follow:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted to produce 2 moles of Al₂O₃.

Therefore, Xmol of Al will react to produce 1.25 moles of Al₂O₃ i.e

Xmol of Al = (1.25 × 4)/2

Xmol of Al = 2.5 moles.

Thus, 2.5 moles of Al is needed for the reaction.

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