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calculate the heat required to change 2.0kg of ice at 0°C to water at 0°C

Sagot :

Answer:

160000 calories or 669440 Joules

Explanation:

Using the formula as follows;

Q = L × m

Where;

Q = amount of heat (J)

L = specific latent heat

m = mass (g)

* Latent heat (L) required for melting of ice is 80 calories/grams.

* Mass of ice in grams = 2kg × 1000 = 2000g.

Hence, Q = 80 × 2000

= 160000 Calories

1 calorie = 4.184J

160000 calorie = 160000 × 4.184

= 669440J