Answer:
[tex] 220.5 \: {yd}^{2} [/tex]
Step-by-step explanation:
Area of the figure = Area of the arc with radius 10 yd and central angle 90° + Area of rectangle with dimensions (10 + 5 - 3 = 12) 12 yd and (7 + 6 - 4 = 9) 9 yd + Area of square with dimension 4yd + Area of rectangle with dimensions 3 yd by 2 yd + Area of triangle with base 3 yd and height (5 + 3 = 8) 8 yd.
[tex] = \frac{90 \degree}{360 \degree} \times 3.14 {(10)}^{2} + 12 \times 9 + {4}^{2} \\ + 3 \times 2 + \frac{1}{2} \times 3 \times 8 \\ \\ = \frac{1}{4} \times 314 + 108 + 16 + 6 + 12 \\ \\ = 78.5 + 142 \\ \\ = 220.5 \: {yd}^{2} [/tex]
