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Sagot :
Answer: Hello Luv.........
34.3 meters. Sorry I'm late.
Step-by-step explanation:
The generic equation for a movement with constant acceleration is:
S = So + Vo*t + (a*t^2)/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
If we compare with our equation (where x is the time and f(x) is the final distance), we have that:
So = 34.3
Vo = 29.4
a = -9.8
So we have that the inicial position (So) of the object is 34.3 meters.
Hope this helps.
Mark me brainest please.
Anna ♥
Answer:
The initial positio34.3 metres .
Step-by-step explanation:
The known equation for a movement
[tex]S = So + Vo*t + (a*t^2)/2[/tex]
Where S is the final position, So is the initial position, Vo is the initial speed, a is the acceleration due to gravity and t is the time taken.
If we compare with our equation (where x is the time and f(x) is the final distance), we have that:
So = 34.3 Vo = 29.4 a = -9.8 m/s^2 because g act downside
Therefore the initial position (So) of the object is 34.3 meters.
Click here to know more about the equation for a movement
https://brainly.com/question/23571852
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