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Sagot :
Answer:
Explanation:
a )
PbS + 2PbO → 3Pb + SO₂
2 mole 3 moles 1 moles
b )
2 moles of PbO is required to produce 3 moles of Pb
17 moles of PbO is required to produce 3/2 x 17 moles of Pb
= 3/2 x 17 moles of Pb
= 25.5 moles of Pb .
c )
1 mole of SO₂ needs 2 moles of PbO
27.3 mole of SO₂ needs 2 x 27.3 moles of PbO
PbO needed = 2 x 27.3 moles
= 54.6 moles .
d )
PbS + 2PbO → 3Pb + SO₂
1 mole 2 mole
1 mole of PbS requires 2 moles of PbO
17.6 mole of PbS requires 2 x 17.6 moles of PbO
PbO required = 2 x 17.6 moles
= 35.2 moles .
PbO available = 36 moles . So PbO is in excess .
Hence PbS is the limiting reagent .
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