Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

In ΔEFG, g = 960 cm, f = 920 cm and ∠F=69°. Find the largest possible value of ∠G, to the nearest degree.

Sagot :

Answer: 77  and 103

Step-by-step explanation:

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

=

b

sinB

From the reference sheet (reciprocal version).

\frac{\sin G}{960}=\frac{\sin 69}{920}

960

sinG

=

920

sin69

Plug in values.

\sin G=\frac{960\sin 69}{920}\approx 0.9741709

sinG=

920

960sin69

≈0.9741709

Evaluate.

G=\sin^{-1}(0.9741709)\approx 76.95\approx 77^{\circ}

G=sin

−1

(0.9741709)≈76.95≈77

Inverse sine and round.

\text{Quadrant II: } 180-77=103^{\circ}

Quadrant II: 180−77=103

Sine is positive in quadrants 1 and 2.

\text{Check for possibility:}

Check for possibility:

No triangle's angles may add to more than 180.

69+77=146^{\circ}\leftarrow \text{Possible}

69+77=146

←Possible

Less than 180.

69+103=172^{\circ}\leftarrow \text{Possible}

69+103=172

←Possible