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At an ice carving competition, each carver starts with a block of ice with the dimensions shown. The block is wrapped in a special reflective material to keep it from melting before the competition starts.

Sagot :

Answer:

52 square feet

Step-by-step explanation:

Given

See attachment for block

Required

How much reflective material is needed (without overlapping)

The question implies that, we calculate the surface area of the material.

Without overlapping, the material will have the same surface area as the block of ice.

The surface area is calculated using:

[tex]SA = 2 * (LW + WH + HL)[/tex]

Where

[tex]W = 4[/tex] --- Width

[tex]L = 2[/tex] --- Length

[tex]H = 3[/tex] --- Height

So, we have:

[tex]SA = 2 * (2 * 4 + 4 * 3 + 3 * 2)[/tex]

[tex]SA = 2 * (8 + 12 + 6)[/tex]

[tex]SA = 2 * 26[/tex]

[tex]SA = 52[/tex]

View image MrRoyal