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A) Calculate the torque required to accelerate the Earth in 7 days from rest to its present angular speed about its axis. (b) Calculate the energy required. (c) Calculate the average power required.

Sagot :

Answer:

A) 1.3013476 × 10²⁸ N·m

b) 2.8618128 × 10²⁹ J

c) 4.73183333 × 10²³ W

Explanation:

The mass of the Earth, M = 5.972 × 10²⁴ kg

The radius of the Earth, R = 6,371 km

The angular speed of the Earth, ω = 2·π/(24 hr) = 7.27220522 × 10⁻⁵ rad/s

The shape of the Earth ≈ Spherical

The moment of inertia of a sphere, I = (2/5)·M·R²

The angular acceleration of the Earth in 7 days from rest its present angular speed, ω, is given as follows;

 α = 7.27220522 × 10⁻⁵ rad/s/((7 × 24 × 60 × 60) s) = 1.2024149 × 10⁻¹⁰ rad/s²  

Torque, τ = I × α

∴ τ = (2/5) × 5.972 × 10²⁴ × 6,731,000² × 1.2024149 × 10⁻¹⁰ = 1.3013476 × 10²⁸

The torque required, τ = 1.3013476 × 10²⁸ N·m

b) The energy required, [tex]K.E. _{(Rotational)}[/tex] = 1/2 × I × ω²

∴  [tex]K.E. _{(Rotational)}[/tex] = (1/2) × (2/5) × 5.972 × 10²⁴ × 6,731,000² × (7.27220522 × 10⁻⁵ rad/s)²

The energy required, [tex]K.E. _{(Rotational)}[/tex] = 2.8618128 × 10²⁹ J

c) Power = Energy/Time

Therefore, the average power required, P = [tex]K.E. _{(Rotational)}[/tex]/Time

∴ P = 2.8618128 × 10²⁹ J/(7 × 24 × 60 × 60) s) = 4.73183333 × 10²³ Watts

The average power required, P = 4.73183333 × 10²³ Watts.